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Difference between revisions of "Episode 1861"
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{{R-letters| 3|NMSAOEGML|MANGLES |MANGLES |MAMELONS* |20|13|21}} | {{R-letters| 3|NMSAOEGML|MANGLES |MANGLES |MAMELONS* |20|13|21}} | ||
{{R-numbers |4|100 |10|5|9|7|9|121 | {{R-numbers |4|100 |10|5|9|7|9|121 | ||
| − | |121|sol1= | + | |121|sol1=100 + 7 + 9 + 5 |
| − | |121|sol2= | + | |121|sol2=(100 + 9 + 10) + (7 - 5) |
| − | |||
|30|23|31}} | |30|23|31}} | ||
{{R-letters| 5|WERIHCEBX|BREECH |CHEWIER | |30|30|38}} | {{R-letters| 5|WERIHCEBX|BREECH |CHEWIER | |30|30|38}} | ||
| Line 23: | Line 22: | ||
{{R-conundrum|9|BIGPAINTS|sol=BAPTISING|53|53|73}} | {{R-conundrum|9|BIGPAINTS|sol=BAPTISING|53|53|73}} | ||
{{R-conundrum|TB|ERIGATION|sol=ORIGINATE|53|53|73}} | {{R-conundrum|TB|ERIGATION|sol=ORIGINATE|53|53|73}} | ||
| − | {{R-conundrum|TB|TOOCHOPPY|c1time= | + | {{R-conundrum|TB|TOOCHOPPY|c1time=4|c1sol=PHOTOCOPY|63|53|73}} |
{{Rounds-end}} | {{Rounds-end}} | ||
{{DEFAULTSORT:1861}} | {{DEFAULTSORT:1861}} | ||
| − | |||
[[Category:Episodes in Series 33]] | [[Category:Episodes in Series 33]] | ||
[[Category:9-round games]] | [[Category:9-round games]] | ||
Revision as of 07:21, 19 September 2010
Episode 1861 was broadcast on 17 October 1996, as the final of Group A in the Supreme Championship.
John Clarke played Don Reid, with John Clarke winning 63 – 53, after 2 tie-break conundrums, and hence becoming the second contestant to reach the finals of the event, joining automatic qualifier Chris Rogers. The Dictionary Corner guest was Philip Franks, and the lexicographer was Susie Dent.
Rounds
| Rnd | Selection | John Clarke | Score | Don Reid | Others | Max. |
|---|---|---|---|---|---|---|
| 1 | TWTIEIDDV | DIVIDE | 6 – 6 | TIDIED | WITTED* | 6 |
| 2 | SDACOSITG | DACOITS | 13 – 6 | DISCOS | SCOTIAS* | 13 |
| 3 | NMSAOEGML | MANGLES | 20 – 13 | MANGLES | MAMELONS* | 21 |
| 4 | 100 10 5 9 7 9 → 121 | 121
100 + 7 + 9 + 5 |
30 – 23 | 121
(100 + 9 + 10) + (7 - 5) |
|
31 |
| 5 | WERIHCEBX | BREECH | 30 – 30 | CHEWIER | 38 | |
| 6 | LRNUOEYBF | FOULER | 36 – 36 | ROUBLE | FLEURON | 45 |
| 7 | HUDOVENDT | HOUNDED | 43 – 43 | HOUNDED | 53 | |
| 8 | 25 1 5 9 2 10 → 721 | 721
(10 × 2 + 9) × 25 − (5 − 1) |
53 – 53 | 721
(10 × 2 + 9) × 25 − (5 − 1) |
|
63 |
| 9 | BIGPAINTS | 53 – 53 | BAPTISING | 73 | ||
| TB | ERIGATION | 53 – 53 | ORIGINATE | 73 | ||
| TB | TOOCHOPPY | PHOTOCOPY
(4 seconds) |
63 – 53 | 73 |
