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Difference between revisions of "Episode 1332"

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[[Chris Waddington]] played [[Robert Teuton]], with Chris Waddington winning {{score|54|44}}. The [[Dictionary Corner]] guest was [[Richard Stilgoe]], and the [[lexicographer]] was [[Susie Dent]].
 
[[Chris Waddington]] played [[Robert Teuton]], with Chris Waddington winning {{score|54|44}}. The [[Dictionary Corner]] guest was [[Richard Stilgoe]], and the [[lexicographer]] was [[Susie Dent]].
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 +
According to Waddington, the [[conundrum]] round was originally set with the answer as {{word|RELAPSING}}, to which he 'incorrectly' buzzed with the answer {{word|SPANGLIER}}. It was then discovered that the word was indeed valid, and so a retake was shot with the original intended answer as the scramble.
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This episode was also fondly remembered by fans of the series for the second [[numbers game]] – as the solution appeared straightforward, Waddington suggested that [[Richard Whiteley]] should attempt to solve it. Whiteley said 25 × 4 + 7 + 5, which equals 112, and [[Carol Vorderman]] helped him spot 25 × 4 + 10 + 3. Therefore, the [[contestant]]s did not reveal their solutions, but it can be assumed they were identical.
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This episode was repeated on 19 June 2000, following the conclusion of {{w|West Indian cricket team in England in 2000#1st Test|England vs West Indies}}.
  
 
==Rounds==
 
==Rounds==
 
{{Rounds-start|Chris Waddington|Robert Teuton}}
 
{{Rounds-start|Chris Waddington|Robert Teuton}}
{{R-letters  |1 |GXDUEISWN|GUIDES  |SWINGED  |EXUDING            |  0|7  |  7}}
+
{{R-letters  |1|GXDUEISWN|GUIDES  |SWINGED  |EXUDING            |  0|7  |  7}}
{{R-letters  |2 |AIEVMPRLS|VAMPIRES |VAMPIRES |IMPALERS*, LEMPIRAS*, PALMIERS*, PREVAILS, PRIMEVAL|  8|15 | 15}}
+
{{R-letters  |2|AIEVMRPLS|VAMPIRES |VAMPIRES |IMPALERS*, LEMPIRAS*, PALMIERS*, PREVAILS, PRIMEVAL|  8|15 | 15}}
{{R-letters  |3 |WRYOAEPGJ|POWER    |POWER    |ROPEWAY*            | 13|20 | 22}}
+
{{R-letters  |3|WRYOAEPGJ|POWER    |POWER    |ROPEWAY*            | 13|20 | 22}}
{{R-numbers  |4 | 75|6|2|2|9|4| 656
+
{{R-numbers  |4| 75|6|2|2|9|4| 656
 
|656 {{x}}
 
|656 {{x}}
 
|—
 
|—
 
|cv=656|solcv=(75 − 2) × 9 − (6 − 4) ÷ 2
 
|cv=656|solcv=(75 − 2) × 9 − (6 − 4) ÷ 2
 
|13|20|32}}
 
|13|20|32}}
{{R-letters  |5 |OIATFVSCE|COSTIVE  |AVOCETS  |ACTIVES*, FACTIVE*, OCTAVES| 20|27 | 39}}
+
{{R-letters  |5|OIATFVSCE|COSTIVE  |AVOCETS  |ACTIVES*, FACTIVE*, OCTAVES| 20|27 | 39}}
{{R-letters  |6 |GPHAEORNF|PROFANE  |GRAPH    |                    | 27|27 | 46}}
+
{{R-letters  |6|GPHAEORNF|PROFANE  |GRAPH    |                    | 27|27 | 46}}
{{R-letters  |7 |IEASNRBRN|BANNERS  |BANNERS  |BARRENS*            | 34|34 | 53}}
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{{R-letters  |7|IEASNRBRN|BANNERS  |BANNERS  |BARRENS*            | 34|34 | 53}}
{{R-numbers  |8 | 25|10|5|7|4|3| 113
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{{R-numbers  |8| 25|10|5|7|4|3| 113
 
|113|sol1=25 × 4 + 10 + 3
 
|113|sol1=25 × 4 + 10 + 3
 
|113|sol2=25 × 4 + 10 + 3
 
|113|sol2=25 × 4 + 10 + 3
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{{R-conundrum|9|RELAPSING|c1time=28|c1sol=SPANGLIER|54|44|73}}
 
{{R-conundrum|9|RELAPSING|c1time=28|c1sol=SPANGLIER|54|44|73}}
 
{{Rounds-end}}
 
{{Rounds-end}}
 
==Notes==
 
According to Waddington, the conundrum round was originally set with the answer as {{word|RELAPSING}}, to which he 'incorrectly' buzzed with the answer {{word|SPANGLIER}}. It was then discovered that the word was indeed valid, and so a retake was shot with the original intended answer as the scramble.
 
 
This episode was also fondly remembered by fans of the series for the second numbers game; as the solution appeared straightforward, Carol suggested that Richard should attempt to solve the number's game. Richard correctly deduced that 25 × 4 = 100, however, he then declared 7 + 5 as the second part of the solution, and added it on to the 100 (in other words, his solution only added up to 112, one short of the target).
 
  
 
==External Links==
 
==External Links==
{{YouTube|g3NSFALZzj8|6vRA1rWfZfA|OJ68w1XnJAk}}
+
{{YouTube|kg84gXjew4A}}
  
 
{{DEFAULTSORT:1332}}
 
{{DEFAULTSORT:1332}}
 
[[Category:Episodes in Championship of Champions VI]]
 
[[Category:Episodes in Championship of Champions VI]]
 
[[Category:9-round games]]
 
[[Category:9-round games]]
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[[Category:Championship of Champions semi-finals]]
 
[[Category:Episodes presented by Richard Whiteley]]
 
[[Category:Episodes presented by Richard Whiteley]]
 
[[Category:Episodes with Carol Vorderman as arithmetician]]
 
[[Category:Episodes with Carol Vorderman as arithmetician]]
 
[[Category:Episodes with Susie Dent as lexicographer]]
 
[[Category:Episodes with Susie Dent as lexicographer]]
 
[[Category:Episodes with Richard Stilgoe as a guest]]
 
[[Category:Episodes with Richard Stilgoe as a guest]]
 +
[[Category:Rematches]]
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[[Category:Repeated episodes]]

Latest revision as of 22:42, 14 May 2023

Episode 1332 was broadcast on 8 January 1993, and was the first semi-final of Championship of Champions VI.

Chris Waddington played Robert Teuton, with Chris Waddington winning 54 – 44. The Dictionary Corner guest was Richard Stilgoe, and the lexicographer was Susie Dent.

According to Waddington, the conundrum round was originally set with the answer as RELAPSING, to which he 'incorrectly' buzzed with the answer SPANGLIER. It was then discovered that the word was indeed valid, and so a retake was shot with the original intended answer as the scramble.

This episode was also fondly remembered by fans of the series for the second numbers game – as the solution appeared straightforward, Waddington suggested that Richard Whiteley should attempt to solve it. Whiteley said 25 × 4 + 7 + 5, which equals 112, and Carol Vorderman helped him spot 25 × 4 + 10 + 3. Therefore, the contestants did not reveal their solutions, but it can be assumed they were identical.

This episode was repeated on 19 June 2000, following the conclusion of England vs West Indies.

Rounds

Rnd Selection Chris Waddington Score Robert Teuton Others Max.
1 GXDUEISWN GUIDES 0 – 7 SWINGED EXUDING 7
2 AIEVMRPLS VAMPIRES 8 – 15 VAMPIRES IMPALERS*, LEMPIRAS*, PALMIERS*, PREVAILS, PRIMEVAL 15
3 WRYOAEPGJ POWER 13 – 20 POWER ROPEWAY* 22
4 75 6 2 2 9 4 → 656 656 ☓ 13 – 20

CV: 656 = (75 − 2) × 9 − (6 − 4) ÷ 2

32
5 OIATFVSCE COSTIVE 20 – 27 AVOCETS ACTIVES*, FACTIVE*, OCTAVES 39
6 GPHAEORNF PROFANE 27 – 27 GRAPH 46
7 IEASNRBRN BANNERS 34 – 34 BANNERS BARRENS* 53
8 25 10 5 7 4 3 → 113 113
25 × 4 + 10 + 3
44 – 44 113
25 × 4 + 10 + 3


63
9 RELAPSING SPANGLIER
(28 seconds)
54 – 44 73


External Links