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Difference between revisions of "Episode CLAN31"

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| style="font-family:'Times New Roman', Times, serif !important;; background-color:#E8E8FF;" | <small>STAIRCON</small> {{x}}
 
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| style="font-family:'Times New Roman', Times, serif !important;; background-color:#E8E8FF;" | GALORE

Revision as of 15:45, 3 April 2024

Episode CLAN31, billed as Celebrity Letters and Numbers Series 3, Episode 7 was a special episode broadcast on 14 November 2022 as part of Celebrity Letters and Numbers.

Anthony 'Lehmo' Lehmann, Alex Lee and Reuben Kaye were the contestants, while Michael Hing reprised his role as the host.

The match saw Lehmo winning by 50 – 35 – 17 and he won an old "Transformers" lunch box from Hing's childhood bedroom.

Lily Serna was, as ever, the arithmetician. The Dictionary Corner guest was Claire Hooper, and the lexicographer was David Astle.

NOTE 1: In this version, three players competing with each other instead of traditional two. Also, this version notably uses a scoring system whereby all players receive points for each valid word or solution, even if beaten by their opponents (equivalent to them receiving their "raw scores").

NOTE 2: In Numbers Rounds of this version, players receive points for their declarations, even if the solutions for players' declarations were not provided in the show, assuming they were cut out from broadcasting to speed up the show. Also, player can get points if their solution leads to the result which not matches with the declared result, but it's still in scoring margin.

Rounds

Rnd Selection Lehmo Alex Lee Reuben Kaye Score Others Max
1 C S O A T N O R I MICROSAT STAIRCON CONTORNI 0 – 0 – 0 CONSORTIA 18
2 E M B G A O R E T BOATER EMBARGO BERGAMOT 6 – 7 – 8 26
3 25 8 7 2 3 1 → 622 624
(7 × 3 + 8 ÷ 2) × 25 − 1
13 – 7 – 8 LS: 622 = ((8 + 1) × 2 + 7) × 25 − 3 36
TTT STARTCAB Start this cab to pick up Kandinsky. ABSTRACT
4 A V E L Y U C O M CLOVE LOCUM MACEY 18 – 12 – 8 VACUOLE, LEUCOMA* 43
5 J I A I C B N E H CHAIN CHAIN BANE 23 – 17 – 12 CHAÎNÉ* 49
6 50 6 1 7 5 3 → 971 962
(6 × 3 + 1) × 50 + 7 + 5
2006 936 28 – 17 – 12 LS: 971 = ((7 − 3) × 50 − 6) × 5 + 1 59
TTT CRABHOLE A single crab hole is gained by a degree. BACHELOR
7 R A E G L O N S A ROLES GALORE NASAL 33 – 23 – 17 SANGREAL 67
8 25 75 2 6 1 5 → 403 404
(75 − 25) × (6 + 2) + 5 − 1
399/407 420 40 – 30 – 17 LS: 403 = (75 + 25) × (5 − 1) + 6 ÷ 2 77
TTT FINALLYUP Finally up, despite maximum hurt. PAINFULLY
9 Z T I O I S U N E ZIONIST INSET TONSUE 40 – 35 – 17 UNITIZES 85
10 B A N E L I L R A BALLERINA
(1.75SECONDS)
50 – 35 – 17 95